For every finite case, I can find a $c$ where $2^n = n^c$, so why is this true?
$$\lim_{n \rightarrow \infty} \frac{2^n}{n^c} = 0$$
From the finite cases it seems like $2^n$ grows faster because we can find a $c$ to match it at any $n$.
For every finite case, I can find a $c$ where $2^n = n^c$, so why is this true?
$$\lim_{n \rightarrow \infty} \frac{2^n}{n^c} = 0$$
From the finite cases it seems like $2^n$ grows faster because we can find a $c$ to match it at any $n$.