where $h>0$. Could someone explain to me how to solve it? I searched the internet and I found the result is $\frac{\sqrt{\pi}}{2\sqrt{h}}$ but I couldn't undersand Gauss error function - that is involved in solving.
Evaluate the definite integral: $\int_0^\infty e^{-hx^2}\;\mathrm{d}x$
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calculus
integration
definite-integrals