I'm looking for an $n \in \Bbb N$ for which $\phi(n) = 40$ where $\phi$ is a Euler-Totient Function
I already found one, namely, $n=41$
How the calculate the $n's$?
I'm looking for an $n \in \Bbb N$ for which $\phi(n) = 40$ where $\phi$ is a Euler-Totient Function
I already found one, namely, $n=41$
How the calculate the $n's$?