I'm a beginner to maths and have trouble simplyfying the following function:
$$\frac{p^y \cdot (pq)^o}{p^{2y+o} \cdot q^{o-2}}$$
The final answer is
$$p^{-y} \cdot q^2$$
But I'm not sure how to get there.
Any help is appreciated.
I'm a beginner to maths and have trouble simplyfying the following function:
$$\frac{p^y \cdot (pq)^o}{p^{2y+o} \cdot q^{o-2}}$$
The final answer is
$$p^{-y} \cdot q^2$$
But I'm not sure how to get there.
Any help is appreciated.
Here's the method in general, without actually working out your example. You should do that yourself to seal the concepts.
The intermediate goal is to get all the powers of p and q separated in both the numerator and denominator. In this case, it's almost there, with the exception of (pq)^o. So expand that first, using the principle (x*y)^a = x^a * y^a.
Then gather the p's and q's using the properties of multiplication and exponentiation, x^a * x^b = x^(a+b). Finally, match the p's in the numerator and denominator, likewise the q's, and using the principle x^a / x^b = x^(a-b) calculate the ultimate powers of p and q. Note that there are two ways you could handle the power of p in the final answer, since it is negative.