For the second one, take a look at the Online Encyclopedia of Integer Sequences[1]. Sequence #A030653 is what you are wanting.
(You can look at [1] for more extensive information including sources, but I will tell a bit about it here.)
Let $a(n)$ be the n-th number of the sequence for $n \in \{1,2,3...\}$.
Then we have that $a(n) = n^{3} + 3n^{2} + 3n - 3$.
Examples:
$a(1) = 1 + 3(1) + 3(1) - 3 = 4$
$a(2) = 8 + 3(4) + 3(2) -3 = 8 + 12 + 6 - 3 = 23$
...
For the next number in the sequence, we need to calculate $a(5)$. Using the formula above, we get,
$a(5) = 125 + 3(25) + 3(5) - 3 = 125 + 75 + 15 -3 = 212$.
So 212 is the next number in the sequence