Edit:
The answers I seem to be getting here are that this is not possible, but I have come across a formulae for subdividing an icosahedron (which I don't have to hand, but goes something like this)
$V = 10 u^2+2$
$E = 30 u^2$
$F = 20 u^2$
Where $u=\text{ frequency of subdivision}$
(I may have it the wrong way around but you get the picture) this allows us to calculate the amount of vertices, edges and faces for each subdivision.
Using this formula (or the correct one anyway) you can incrediment the frequency untill the number of faces reach 1000. It would appear in theory this will allow me to imitate a sphere with 1000 congruent polygon's (faces) by constructing a subdivided icosahedron because using $V-E+F=2$ I get $502-1500+1000=2$
Can anyone confirm if the faces will wrap around to make a full icosahedron without any missing faces?
Know the answer? reply and you will most likely get the vote.
Thanks!
Complete icosahedron with $20,40,80,120,160,200,240,280,320...1000$ faces, is it true?
Hi, Does anyone know if it possible to represent a sphere with $1000$ equal surfaces?
When I say equal surfaces, I am talking in terms of area. However it would also be preferable if the shape of these surfaces match.
For example, I am looking at subdivided icosahedrons, all surfaces are equal triangles in terms of shape and area, but to produce a nice sphere it would seem the number of surfaces would need to be $20, 80, 320$ etc.
Also I have come across zonohedrons - Does this allow any amount of surface? I can see that the surfaces are different shapes (but i should hope they have the same area)
I know this may sound a bit confusing, but any feedback will be much appreciated.