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$\begingroup$

Please help - in my notes, it is the group $V$ itself. I just want to confirm this. Can you also explain and give an example if that is possible?

2 Answers 2

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Every abelian group is its own center. If you look at the definitions you will see this.

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    alright!! thanks! :))2010-09-30
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You know, this group has only 4 elements. You could just multiply them out. Really, there are only three worthwhile elements, as one is an identity and that commutes with everything.

It would take less than 5 minutes, and you could do it Cayley style or full-on multiplication table style. It would probably even be good for you, as you might get a feel for what groups really are.

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    You're answering to a thread more than a year old. I hope OP has figured it out by now :)2011-12-13
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    Besides - Cayley graphs don't make you feel what groups really are.2011-12-13
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    @t.b. Oh... Zev edited the question 14 hours ago, and I never pay attention to original post dates. So I thought I was answering an hour-old thread. Whoops.2011-12-13
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    @Martin: I never said cayley graphs would make him get a good feel, I said carrying out the multiplication would. I think this problem demonstrated a lack of understanding of group computation, that's all.2011-12-13