I need to solve this :$$ z^2 -6z + 25 = 0$$
My book says 'complete the square' so :
1.$$ (z - 6/2)^2 -36/4 + 25 $$
2.$$ (z - 3)^2 -9 + 25 $$
3.$$ (z - 3)^2 + 16 $$
Now how exactly does the above turn into this:
$$ 3\pm 4\imath $$
Thanks so Much
Gideon