(1/8)(3m - 5) = (6/5)(6m - 2) + 5...Type your answer as a fraction. Do not use decimals!
**i got -129/273 is this correct ?
(1/8)(3m - 5) = (6/5)(6m - 2) + 5...Type your answer as a fraction. Do not use decimals!
**i got -129/273 is this correct ?
Assuming you mean: $\frac{1}{8}(3m - 5) = \frac{6}{5}(6m - 2) + 5$
You would solve as:
$$40 * \frac{1}{8}(3m - 5) = 40 * (\frac{6}{5}(6m - 2) + 5)$$
$$5 * (3m - 5) = (48 * (6m - 2)) + 200$$
$$15m - 25 = 288m - 96 + 200$$
$$15m - 25 = 288m + 104$$
$$-129 = 273m$$
$$m = -\frac{129}{273} = -\frac{43}{91}$$
Assuming you mean $\frac{1}{8(3m - 5)} = \frac{6}{5(6m - 2)} + 5$
You would solve as:
$$\frac{1}{24m - 40} = \frac{6}{30m - 10} + 5$$
$$(30m - 10)(24m - 40) * \frac{1}{24m - 40} = (30m - 10)(24m - 40) * (\frac{6}{30m - 10} + 5)$$
$$30m - 10 = 24m - 40 + (5*(30m - 10)(24m - 40))$$
$$30m - 10 = 24m - 40 + (5 * (720m^2 - 1140m + 400))$$
$$30m - 10 = 24m - 40 + 3600m^2 - 7200m + 2000$$
$$0 = 3600m^2 - 7206m + 1970$$
$$m = \frac{1201 \pm \sqrt{654401}}{1200}$$
(I would double check the work on both of these though, I'm tired =/)