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$$ ((n+1)H_n - (n+1)) + H_{n+1} = (n+2)H_{n+1} - (n+2) $$ I need to prove the above statement.

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    doesn't merely using the definition of $H_n$ work?2010-11-03
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    $H_{n+1}=H_n+1/(n+1)$2010-11-03
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    I should have added that I had gotten that far, but I can't figure what to do with that.2010-11-03
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    @Mark: cancel as many terms as you can.2010-11-03
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    Do you really need to prove it by induction? In my answer I assumed not.2010-11-03
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    It's part of an inductive proof ($H_1+H_2+...+H_n = (n+1)H_n - (n+1)$)2010-11-03
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    Thanks for all the help, I've now fully proven the statement.2010-11-03

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