AB+CD+A’BD+A’BC+AB’D+AB’C AB+CD+A’B(D+C)+AB’(D+C) CD+(AB+A'B(D+C)+AB’(D+C)) CD+(AB+B(D+C)+A(D+C)) CD+AB+(B(D+C)+A(D+C)) CD+AB+(A+B)(D+C)
This is what I got, but I'm not sure if it's correct. It's as good as I can get it algebraically. Can it be simplified further?