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If a quantity is successively increased by 20% for two times and another quantity is successively decreased by 10% for three times, the first quantity is 80% of the second. What percentage is the original first quantity as compared to the original second quantity?

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    Why do you want to know? What have you tried?2010-10-15
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    Well,I derived the answer as `73%` with rather a brute force approach and not probably helpful during exam.2010-10-15
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    @Tretwick: That is the result you got, not the idea you used. How did you arrive at that result?2010-10-15

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