What is $x$ in closed form if $2x-\sin2x=\pi/2$, $x$ in the first quadrant?
Solving $2x - \sin 2x = \pi/2$ for $0 < x < \pi/2$
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trigonometry
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0Yes. But it seems from other posters' answers, there is no known one due to $cosy=y$. – 2010-11-15