How does one go about solving the following quadratic congruence?
$4x^2 \equiv 2 \ (\text{mod} \ 7)$
number-theory
asked 2010-10-29
user id:2868
41
33bronze badges
5
Gonna say the same thing I said to you last time: "In congruences, you can replace either side with that same thing plus a multiple of p." – 2010-10-29