Can we find $f(x)$ given that $1-f(x) = f(-x)$ for all real $x$?
I start by rearranging to: $f(-x) + f(x) = 1$. I can find an example such as $f(x) = |x|$ that works for some values of $x$, but not all. Is there a method here? Is this possible?
Can we find $f(x)$ given that $1-f(x) = f(-x)$ for all real $x$?
I start by rearranging to: $f(-x) + f(x) = 1$. I can find an example such as $f(x) = |x|$ that works for some values of $x$, but not all. Is there a method here? Is this possible?