Is it true or false that a group of order 12 always has a normal 2-sylow subgroup? I have a hunch it is false..
Group of order 12
7
$\begingroup$
group-theory
finite-groups
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1Do you know examples of nonabelian groups of order 12? – 2010-12-18
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0Hint: Try to find a non-abelian group of order 12 with a normal 3-Sylow. To do this it will be helpful to understand the semidirect product construction (see http://en.wikipedia.org/wiki/Semidirect_product). – 2010-12-18
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0I do not know how to classify them, but I know there is either a normal 3-subgroup or a normal 2-subgroup. – 2010-12-18
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0You don't need to classify them, just an example. One way to get them is to take products or semidirect products of smaller groups (whose orders multiply to 12). – 2010-12-18
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0say $Z_3\rtimes Z_4$? – 2010-12-18
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0@Gargle: Yes, so long as the action is nontrivial, that should do. – 2010-12-18
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0I think I have constructed a counter example, but why is that? I cannot see that this is a counter example. (I am terrible at 'seeing' things in algebra) – 2010-12-18
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5Dear Gargle, Write down a 2-Sylow subgroup in your example, and start conjugating it. (There are only 12 elements to conjugate by!) If you have trouble "seeing" things, then just compute. (This is an advantage of algebra --- one can always just start computing and see what happens.) – 2010-12-18