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Hey, sorry for the non so mathematical question but that's the only place where I'd thought someone would answer this so here we go.

I'm doing a chemistry homework and I have to answer this very question:

If 50 grams of a particular mineral containing copper nitrate (II) gave, after appropriate treatment 1.6933 grams of pure copper. For this ore, determine the percentage content by weight of copper and the percentage content by weight of copper nitrate (II) in ore.

Could someone help with this please?

Thanks, any help will be very much appreciated :)

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    Content of copper: (1.6933 / 50) 100 = 3.38 %.2010-10-05
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    That is exactly what I wanted to know! Post it back into an answer and I'll give you a good answer :)2010-10-05
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    Thanks a LOT by the way! :)2010-10-05
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    For the content of copper nitrate (II), see J.M's explanation.2010-10-06

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